Simple PHP Script to show latest jpg in all subdirectories
$10-30 AUD
Πληρώθηκε κατά την παράδοση
Hey freelancers,
I need a simple PHP script that will do the following:
- Search all subdirectories starting with '20' (subdirectories start with the year)
- Find the latest image that exists
- Display that image
That's it.. simple..
Please start your bid with the word "sunshine" so I know you're not a bot.
Thanks.
Ταυτότητα Εργασίας: #17781156
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Ανατέθηκε στον:
sunshine: hi sir my name is jestoni, im good developer i can finish this fast im good in php scripting
14 freelancers κάνουν προσφορές κατά μέσο όρο $24 για αυτή τη δουλειά
sunshine Hi, i hope you're doing well. I've just read your project's description and i would like to help you with it. I'm an experienced web developer with the necessary skills for getting this job done. R Περισσότερα
Hello, I can create this script for you starting now and have it delivered in 2-3 hours. Let me know if you are interested. Thank you.
sunshine. Hi, thanks for posting an interesting project. We can easily use recursive scan on directory files. Then we can easily run through all image names and extract paths which starts with '20' I'm an expe Περισσότερα
-----Hello Sir,I can do that your full project .Ready to start Now and completed ASAP "----------- Thanks Reply
"Sunshine" Hello, I am expert web developer with 5 years of experience. I assure you that I can make script for latest image viewing according to your requirements. I am ready to start work right now and you can pay Περισσότερα
Hello, I am happy to assist you with PHP development. I have 2+ year of experience in PHP, MySQL,HTML,CSS,Bootstrap. Thank You. Ayush G.
sunshine A PHP/MYSQL DEVELOPER MYSELF...NOT AN AGENCY OR MIDDLEMAN WHO OUTSOURCES THEIR WORK. With an overall experience of 12 years in creation and development of digital properties and online marketing activiti Περισσότερα
Sunshine i am sure if this is same thing that you had asked to do so as to make sure iam not a bot.☝️sunshine one. Regarding the script its doable but need more info to get a good idea to implement it efficiently!!